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J Appl Physiol 86: 1025-1031, 1999;
8750-7587/99 $5.00
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Vol. 86, Issue 3, 1025-1031, March 1999

The maximum shortening velocity of muscle should be scaled with activation

John W. Chow1 and Warren G. Darling2

1 Department of Kinesiology, University of Illinois at Urbana-Champaign, Urbana, Illinois 61801; and 2 Department of Exercise Science, University of Iowa, Iowa City, Iowa 52242

The purpose of this study was to determine whether the maximum shortening velocity (Vmax) in Hill's mechanical model (A. V. Hill. Proc. R. Soc. London Ser. B. 126: 136-195, 1938) should be scaled with activation, measured as a fraction of the maximum isometric force (Fmax). By using the quick-release method, force-velocity (F-V) relationships of the wrist flexors were gathered at five different activation levels (20-100% of maximum at intervals of 20%) from four subjects. The F-V data at different activation levels can be fitted remarkably well with Hill's characteristic equation. In general, the shortening velocity decreases with activation. With the assumption of nonlinear relationships between Hill constants and activation level, a scaled Vmax model was developed. When the F-V curves for submaximal activation were forced to converge at the Vmax obtained with maximum activation (constant Vmax model), there were drastic changes in the shape of the curves. The differences in Vmax values generated by the scaled and constant Vmax models were statistically significant. These results suggest that, when a Hill-type model is used in musculoskeletal modeling, the Vmax should be scaled with activation.

force-velocity relationship; Hill model; wrist flexors


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